Lateral Torsional Buckling (LTB) — Definition, Formula & Prevention
Lateral torsional buckling (LTB) is a stability limit state that governs the flexural capacity of steel beams without full lateral restraint. When a beam bends about its major axis, the compression flange acts like a column under axial compression. If the beam is not laterally braced at sufficiently close intervals, the compression flange buckles sideways, and the entire cross-section simultaneously twists. This coupled lateral displacement and torsional rotation defines LTB as a distinct failure mode from simple flexural yielding or local buckling.
LTB is the controlling limit state for most unbraced steel beams. Understanding the critical moment, the moment gradient factor Cb, and the unbraced length thresholds Lp and Lr is essential for economical beam design under AISC 360, AS 4100, EN 1993, and CSA S16.
Physical Mechanism of LTB
PRELIMINARY — NOT FOR CONSTRUCTION. All content is for educational and reference use only. Must be independently verified by a licensed Professional Engineer (PE) or Structural Engineer (SE) before use in any project.
When a beam is loaded in strong-axis bending, the top flange experiences compression while the bottom flange experiences tension. The compression flange, being analogous to a column, wants to buckle laterally. However, unlike an isolated column, the compression flange is connected to the tension flange through the web. The tension flange resists lateral movement because it is under tension and wants to remain straight. This interaction produces the twisting (torsional) component of LTB.
Key parameters governing LTB resistance:
| Parameter | Symbol | Effect on LTB Resistance |
|---|---|---|
| Unbraced length | Lb | Shorter Lb = higher resistance |
| Minor-axis moment of inertia | Iy | Higher Iy = stiffer laterally = higher resistance |
| Torsional constant | J | Higher J = greater twist resistance |
| Warping constant | Cw | Higher Cw = greater resistance (I-shapes have large Cw) |
| Moment gradient | Cb | Non-uniform moment = higher Cb = higher resistance |
| Yield stress | Fy | Higher Fy increases plastic moment but makes buckling more critical |
Code Provisions for LTB
AISC 360-22 Chapter F2 — I-Shaped Members
The nominal flexural strength Mn for LTB is governed by the unbraced length Lb relative to two threshold values: Lp (limiting unbraced length for full plastic moment) and Lr (limiting unbraced length for inelastic buckling).
Plastic limit (Lb <= Lp):
Mn = Mp = Fy * Zx
No LTB reduction. The beam can reach full plastic moment capacity.
Inelastic LTB range (Lp < Lb <= Lr):
Mn = Cb * [Mp - (Mp - 0.7*Fy*Sx) * (Lb - Lp) / (Lr - Lp)] <= Mp
Linear interpolation between Mp and 0.7FySx.
Elastic LTB range (Lb > Lr):
Mn = Fcr * Sx <= Mp
Fcr = Cb * pi^2 * E / (Lb/rts)^2 * sqrt(1 + 0.078 * J*c / (Sx*ho) * (Lb/rts)^2)
Where rts is the effective radius of gyration for LTB and c is a section property.
Lp and Lr formulas (AISC 360-22):
Lp = 1.76 * ry * sqrt(E/Fy)
Lr = 1.95 * rts * E / (0.7*Fy) * sqrt(J*c / (Sx*ho) + sqrt((J*c/(Sx*ho))^2 + 6.76*(0.7*Fy/E)^2))
AS 4100 Section 5.6 — Member Capacity with LTB
AS 4100 uses a different approach based on the member slenderness reduction factor alpha_s:
Mb = alpha_m * alpha_s * Ms <= Ms
Where:
- alpha_m = moment modification factor (equivalent to Cb)
- alpha_s = slenderness reduction factor based on the reference buckling moment Mo
- Ms = nominal section moment capacity
The reference buckling moment Mo is computed as:
Mo = sqrt((pi^2*E*Iy)/(Lb^2)) * sqrt(G*J + (pi^2*E*Iw)/(Lb^2))
The slenderness reduction factor alpha_s follows a modified AISC curve:
lambda_s = sqrt(Ms/Mo)
alpha_s = 0.6 * (sqrt(lambda_s^2 + 3) - lambda_s)
EN 1993-1-1 Clause 6.3.2 — Lateral Torsional Buckling
The Eurocode uses the non-dimensional slenderness lambda_LT:
lambda_LT = sqrt(Wy*fy / Mcr)
Where Wy is the appropriate section modulus (plastic or elastic) and Mcr is the elastic critical buckling moment.
The reduction factor chi_LT is determined from:
chi_LT = 1 / (phi_LT + sqrt(phi_LT^2 - lambda_LT^2)) <= 1.0
phi_LT = 0.5 * [1 + alpha_LT * (lambda_LT - 0.2) + lambda_LT^2]
The buckling curve selection (alpha_LT = 0.21, 0.34, 0.49, or 0.76) depends on the cross-section type and h/b ratio.
CSA S16 Clause 13.6 — Lateral Torsional Buckling
CSA S16 is similar to AISC 360 in concept but uses phi = 0.9 for beam design:
When Mu <= 2*Myr/3: Mr = phi * Mu (elastic LTB)
When 2*Myr/3 < Mu <= Myr: Mr = 1.15*phi*Mp * (1 - 0.28*Mp/Mu) (inelastic LTB)
Where Mu is the elastic LTB resistance and Myr = 0.7FySx.
Cb — Moment Gradient Factor
The moment gradient factor Cb accounts for non-uniform moment distribution along the unbraced length. A beam with a uniform moment (Cb = 1.0) is the worst case because the entire compression flange is stressed equally. A beam with moment reversal (Cb up to 3.0) has far greater LTB resistance.
AISC 360 Cb Formula:
Cb = 12.5*Mmax / (2.5*Mmax + 3*MA + 4*MB + 3*MC) * Rm <= 3.0
Where Mmax is the absolute maximum moment, MA, MB, MC are absolute moments at quarter points, and Rm = 1.0 for singly-symmetric sections.
Typical Cb values:
| Loading Condition | Cb (approx.) |
|---|---|
| Uniform moment | 1.00 |
| Center point load, simple span | 1.32 |
| Uniformly distributed load, simple span | 1.14 |
| End moments, M1/M2 = -1.0 (double curvature) | 2.27 |
| End moments, M1/M2 = 0.5 (single curvature) | 1.67 |
| Cantilever, tip load | 1.28 |
| End moments, M1/M2 = 0 (zero at one end) | 1.75 |
A properly computed Cb can increase LTB capacity by a factor of 2-3x, potentially eliminating the need for additional bracing.
Worked Example — LTB Capacity
Problem: Determine the LTB capacity of a W24x55 beam (A992 steel, Fy = 50 ksi) spanning 30 ft with a uniformly distributed load. The compression flange is laterally braced at 10 ft intervals (Lb = 10 ft = 120 in).
Section Properties (W24x55):
- Sx = 114 in^3, Zx = 134 in^3
- Iy = 29.1 in^4, J = 1.19 in^4, Cw = 3700 in^6
- ry = 1.34 in, rts = 2.68 in, ho = 22.9 in, c = 1.0
Step 1: Compute Lp and Lr
Lp = 1.76 * 1.34 * sqrt(29000/50) = 1.76 * 1.34 * 24.08 = 56.8 in = 4.73 ft
Lr = 1.95 * 2.68 * 29000/(0.7*50) * sqrt(1.19*1.0/(114*22.9) + sqrt((1.19/(114*22.9))^2 + 6.76*(0.7*50/29000)^2))
Lr = 167 in = 13.9 ft
Step 2: Determine LTB regime Lb = 10 ft. Lp = 4.73 ft. Lr = 13.9 ft. Lp < Lb <= Lr: Inelastic LTB range.
Step 3: Compute Cb For a uniformly loaded simple span with symmetric bracing points, Cb = 1.14 (interior unbraced segment).
Step 4: Compute Mn
Mp = 50 * 134 / 12 = 558 ft-kip
0.7*Fy*Sx = 0.7 * 50 * 114 / 12 = 332.5 ft-kip
Mn = 1.14 * [558 - (558 - 332.5) * (10 - 4.73) / (13.9 - 4.73)]
Mn = 1.14 * [558 - 225.5 * 5.27 / 9.17]
Mn = 1.14 * [558 - 129.5]
Mn = 1.14 * 428.5 = 488.5 ft-kip
Check: Mn <= Mp = 558 ft-kip. 488.5 < 558, OK.
Step 5: Design strength phiMn = 0.90 * 488.5 = 439.7 ft-kip (LRFD).
If Lb were reduced to 5 ft (near Lp), phiMn = 0.90 * 558 = 502 ft-kip. The 10-ft unbraced length causes a 12.4% reduction from full plastic capacity.
Preventing LTB — Design Strategies
| Strategy | Description | Effectiveness |
|---|---|---|
| Reduce unbraced length | Add intermediate lateral bracing to compression flange | Most effective — Lp threshold effect |
| Select stockier sections | Wider flanges = higher Iy and J | Effective (e.g., W14 vs W24 of similar weight) |
| Provide continuous restraint | Metal deck or concrete slab attached to top flange | Very effective for positive moment regions |
| Increase Cb | Design moment connections to produce moment reversal | Up to 3x capacity increase |
| Use closed sections | HSS tubes have very high torsional stiffness | Virtually eliminates LTB |
| Provide torsional restraint | End plates, stiffeners, or channel stiffeners at supports | Reduces effective length |
Bracing force requirement (AISC 360 Appendix 6):
Pbr = 0.01 * Mr * Cd / ho
Where Mr is the required flexural strength, Cd = 1.0 for single curvature and 2.0 for double curvature, and ho is the distance between flange centroids.
Frequently Asked Questions
What is lateral torsional buckling? Lateral torsional buckling is a stability failure mode in steel beams where the compression flange buckles laterally and the cross-section twists simultaneously. It occurs when the unbraced length exceeds the plastic limit Lp, reducing flexural capacity below the full plastic moment.
When is LTB most critical in design? LTB is most critical for long-span girders with minimal lateral bracing, cantilever beams, crane runway girders, and beams with narrow flanges (low Iy). It is rarely critical for beams with continuous lateral restraint from a concrete slab or closely spaced purlins.
How does Cb affect LTB capacity? Cb, the moment gradient factor, accounts for non-uniform moment distribution along the unbraced length. A beam with moment reversal (Cb = 2.0-2.5) can resist 2-2.5 times the uniform-moment LTB capacity. Cb is always >= 1.0 per AISC 360.
What is the difference between Lp and Lr? Lp is the limiting unbraced length below which no LTB reduction occurs (full plastic capacity Mp). Lr is the limiting unbraced length above which elastic LTB governs. Between Lp and Lr, inelastic LTB applies with linear moment reduction. For A992 W-shapes, Lp typically ranges from 4 to 12 ft.
How do AS 4100 and EN 1993 treat LTB differently? AS 4100 uses a slenderness reduction factor alpha_s based on the reference buckling moment Mo and moment modification factor alpha_m. EN 1993-1-1 uses the buckling reduction factor chi_LT with buckling curve selection based on section geometry. Both produce similar results to AISC 360 but with different intermediate steps and notation.
Related Terms and Pages
- Compact Section — Definition & Limits
- Plastic Modulus — Definition & Formula
- Elastic Section Modulus — Definition & Formula
- Radius of Gyration — Definition & Calculation
- Effective Length Factor — K Factor Guide
- Beam Capacity Calculator — Free Online Tool
- Beam Deflection Calculator
- Steel Beam Design Guide — AISC 360
- Section Properties Database
Educational reference only. Lateral torsional buckling must be checked per the governing design code (AISC 360 Chapter F, AS 4100 Section 5.6, EN 1993-1-1 Clause 6.3.2, or CSA S16 Clause 13.6) by a licensed Professional Engineer for all construction applications.
Disclaimer: This content is for educational purposes only. Results must be verified by a licensed professional engineer. Steel Calculator provides preliminary design tools — NOT a substitute for professional engineering judgment.