---------------- | ------------------- | | Design compression | N_Ed = 1,200 kN | | Buckling length y-y | L_cr,y = 4.0 m | | Buckling length z-z | L_cr,z = 4.0 m |
Section properties (from SCI P363 Blue Book — 203ÃÂÃÂ203ÃÂÃÂ60 UKC):
| Property | Value |
|---|---|
| Depth h | 209.6 mm |
| Width b | 205.8 mm |
| Web thickness tw | 9.4 mm |
| Flange thickness tf | 14.2 mm |
| Root radius r | 10.2 mm |
| Area A | 76.4 cmÃÂò |
| Iy | 6,090 cmâÃÂô |
| Iz | 2,060 cmâÃÂô |
| iy | 8.93 cm |
| iz | 5.20 cm |
| Wpl,y | 654 cmÃÂó |
Material: S355JR steel to EN 10025-2
| Parameter | Value |
|---|---|
| fy (tf âÃÂä 16 mm) | 355 N/mmÃÂò |
| fu (3 < tf âÃÂä 100 mm) | 470 N/mmÃÂò |
| E | 210,000 N/mmÃÂò |
| ÃÂó_M0 (UK NA) | 1.00 |
| ÃÂó_M1 (UK NA) | 1.00 |
| ÃÂõ = âÃÂÃÂ(235/fy) | âÃÂÃÂ(235/355) = 0.814 |
Step 1 — Section Classification (Table 5.2)
Flange Classification
The flange is an outstand compression part in uniform compression:
c = (b - tw - 2r) / 2 = (205.8 - 9.4 - 20.4) / 2 = 88.0 mm
c / tf = 88.0 / 14.2 = 6.20
Limiting c/tf ratios per Table 5.2 (outstand flange in compression):
| Class | Limit | c/tf | Result |
|---|---|---|---|
| 1 | 9ÃÂõ = 9 ÃÂà0.814 = 7.33 | 6.20 âÃÂä 7.33 | Class 1 âÃÂà|
Web Classification
The web is an internal compression part in uniform compression:
cw = h - 2tf - 2r = 209.6 - 28.4 - 20.4 = 160.8 mm
cw / tw = 160.8 / 9.4 = 17.1
Limiting cw/tw ratios per Table 5.2 (web in uniform compression):
| Class | Limit | cw/tw | Result |
|---|---|---|---|
| 1 | 33ÃÂõ = 33 ÃÂà0.814 = 26.9 | 17.1 âÃÂä 26.9 | Class 1 âÃÂà|
Result: Section is Class 1 — full plastic compression resistance may be used.
Step 2 — Cross-Section Compression Resistance Nc,Rd (Cl. 6.2.4)
For a Class 1, 2 or 3 cross-section in uniform compression:
Nc,Rd = A ÃÂàfy / ÃÂó_M0
= 76.4 ÃÂà10ÃÂò ÃÂà355 / 1.00
= 2,712 ÃÂà10ÃÂó N
= 2,712 kN
Utilization: N_Ed / Nc,Rd = 1,200 / 2,712 = 0.44 âÃÂà(44%)
The cross-section is adequate by a wide margin. However, for a slender pin-ended column, flexural buckling will govern (Step 3).
Step 3 — Flexural Buckling Resistance Nb,Rd (Cl. 6.3.1)
3a — Non-Dimensional Slenderness
ÃÂûâÃÂà= ÃÂàÃÂàâÃÂÃÂ(E / fy) = ÃÂàÃÂàâÃÂÃÂ(210,000 / 355) = 76.4
For each axis:
ÃÂû_bar_y = (L_cr,y / iy) / ÃÂûâÃÂà= (4,000 / 89.3) / 76.4 = 44.8 / 76.4 = 0.587
ÃÂû_bar_z = (L_cr,z / iz) / ÃÂûâÃÂà= (4,000 / 52.0) / 76.4 = 76.9 / 76.4 = 1.007
The z-z axis governs (higher slenderness).
3b — Buckling Curve Selection (Table 6.2)
For hot-rolled I-sections under compression, the buckling curve depends on the section geometry:
h / b = 209.6 / 205.8 = 1.02 âÃÂä 1.2 tf = 14.2 mm âÃÂä 100 mm
| Axis | Curve | ÃÂñ (imperfection factor) |
|---|---|---|
| y-y | b | 0.34 |
| z-z | c | 0.49 |
Use curve c (governing axis with ÃÂñ = 0.49).
3c — Reduction Factor ÃÂÃÂ_z
ÃÂæ = 0.5 ÃÂà[1 + ÃÂñ ÃÂà(ÃÂû_bar - 0.2) + ÃÂû_barÃÂò]
= 0.5 ÃÂà[1 + 0.49 ÃÂà(1.007 - 0.2) + 1.007ÃÂò]
= 0.5 ÃÂÃÂ [1 + 0.49 ÃÂÃÂ 0.807 + 1.014]
= 0.5 ÃÂÃÂ [1 + 0.395 + 1.014]
= 0.5 ÃÂÃÂ 2.409 = 1.205
ÃÂÃÂ_z = 1 / [ÃÂæ + âÃÂÃÂ(ÃÂæÃÂò - ÃÂû_barÃÂò)]
= 1 / [1.205 + âÃÂÃÂ(1.205ÃÂò - 1.007ÃÂò)]
= 1 / [1.205 + âÃÂÃÂ(1.452 - 1.014)]
= 1 / [1.205 + âÃÂÃÂ0.438]
= 1 / [1.205 + 0.662]
= 1 / 1.867 = 0.536
3d — Buckling Resistance
Nb,Rd,z = ÃÂÃÂ_z ÃÂàA ÃÂàfy / ÃÂó_M1
= 0.536 ÃÂà76.4 ÃÂà10ÃÂò ÃÂà355 / 1.00
= 1,454 ÃÂà10ÃÂó N
= 1,454 kN
Utilization: N_Ed / Nb,Rd,z = 1,200 / 1,454 = 0.83 âÃÂà(83%)
The column is adequate for flexural buckling. The 17% margin is typical for a moderately loaded column at this slenderness.
3e — Check y-y Axis (Informative)
For completeness, checking the y-y axis even though z-z governs:
From curve b (ÃÂñ = 0.34):
ÃÂæ_y = 0.5 ÃÂà[1 + 0.34 ÃÂà(0.587 - 0.2) + 0.587ÃÂò]
= 0.5 ÃÂÃÂ [1 + 0.34 ÃÂÃÂ 0.387 + 0.345]
= 0.5 ÃÂÃÂ [1 + 0.132 + 0.345]
= 0.5 ÃÂÃÂ 1.477 = 0.739
ÃÂÃÂ_y = 1 / [0.739 + âÃÂÃÂ(0.739ÃÂò - 0.587ÃÂò)]
= 1 / [0.739 + âÃÂÃÂ(0.546 - 0.345)]
= 1 / [0.739 + 0.448]
= 1 / 1.187 = 0.842
Nb,Rd,y = 0.842 ÃÂà76.4 ÃÂà10ÃÂò ÃÂà355 / 1.00 = 2,284 kN
Utilization: 1,200 / 2,284 = 0.53 âÃÂà(53%) — significantly less critical as expected.
Step 4 — Combined Buckling Curve Comparison
The difference between buckling curves under EN 1993-1-1 is significant. For this column (ÃÂû_bar_z = 1.007):
| Curve | ÃÂñ | ÃÂà| Nb,Rd (kN) | Utilization |
|---|---|---|---|---|
| a | 0.21 | 0.653 | 1,772 | 0.68 |
| b | 0.34 | 0.590 | 1,601 | 0.75 |
| c | 0.49 | 0.536 | 1,454 | 0.83 |
| d | 0.76 | 0.444 | 1,204 | 1.00 âÃÂà|
This illustrates why the correct buckling curve selection per Table 6.2 is critical — using curve d would predict failure, while curve a would be unconservative.
Step 5 — Summary
| Check | Governing Clause | Utilisation | Status |
|---|---|---|---|
| Section classification | Table 5.2 | Class 1 | âÃÂà|
| Compression resistance Nc,Rd | Cl. 6.2.4 | 0.44 (44%) | âÃÂà|
| Flexural buckling Nb,Rd (z-z, curve c) | Cl. 6.3.1 | 0.83 (83%) | âÃÂà|
| Flexural buckling Nb,Rd (y-y, curve b) | Cl. 6.3.1 | 0.53 (53%) | âÃÂà|
Conclusion: A 203ÃÂÃÂ203ÃÂÃÂ60 UKC in S355 steel is adequate for the design axial load of 1,200 kN, governed by flexural buckling about the minor axis at 83% utilisation. The section is Class 1, allowing full plastic section resistance. The correct selection of buckling curve per Table 6.2 is critical — curve c applies for UKC sections (h/b âÃÂä 1.2) about the minor axis.
This worked example is for educational purposes. All designs must be verified by a qualified engineer. Use the EN 1993 column buckling calculator to check other sections or load cases.