Steel Truss Design — Member Sizing, Connections & Slenderness

Steel truss design: Pratt vs Warren configurations, chord and web member sizing, KL/r limits, gusset plate connections, secondary bending effects, and deflection control.

Truss fundamentals

A truss is an assembly of straight members connected at joints (nodes) to form a stable triangulated framework. Applied loads at the nodes produce only axial forces in the members (tension or compression) when the joints are idealized as pins. In reality, gusset plate connections provide partial fixity that generates secondary bending moments, but the primary load path remains axial.

Trusses are used for roof structures (spans 15-60 m), transfer girders, pedestrian bridges, and long-span floor systems. The main advantage over rolled beams is that trusses achieve very high span-to-depth ratios — typically span/10 to span/15 — using relatively light members.

Common truss types

Worked example — Pratt roof truss

Span = 24 m, depth = 2.4 m (span/10), 6 panels at 4 m each. Factored uniform load on top chord = 8 kN/m (from purlins at 2 m spacing). Steel grade: A992 (Fy = 345 MPa).

Total factored load W = 8 x 24 = 192 kN. Reactions = 96 kN each.

Maximum chord force (at mid-span): M_max = wL^2/8 = 8 x 24^2 / 8 = 576 kN-m. Chord force = M / depth = 576 / 2.4 = 240 kN. Top chord in compression, bottom chord in tension.

Top chord design (compression): unbraced length between panel points = 4.0 m. Out-of-plane bracing from purlins at 2.0 m, so Lx = 4.0 m (in-plane), Ly = 2.0 m (out-of-plane). Using 2L75x75x6 back-to-back (A = 17.4 cm^2, rx = 2.28 cm, ry = 3.52 cm with 10 mm gap).

KLx/rx = 4000/22.8 = 175. KLy/ry = 2000/35.2 = 57. In-plane slenderness governs. Fe = pi^2 x 200,000 / 175^2 = 64.4 MPa. Since Fe < 0.44Fy, Fcr = 0.877 x 64.4 = 56.5 MPa. phi*Pn = 0.9 x 56.5 x 1740 / 1000 = 88.5 kN. Insufficient for 240 kN.

Increase to 2L100x100x8 (A = 30.8 cm^2, rx = 3.04 cm): KLx/rx = 4000/30.4 = 132. Fe = pi^2 x 200,000 / 132^2 = 113 MPa. Fcr = 0.658^(345/113) x 345 = 97.5 MPa. phi*Pn = 0.9 x 97.5 x 3080 / 1000 = 270 kN > 240 kN. OK.

Bottom chord design (tension): Pu = 240 kN. Required Ag = 240,000 / (0.9 x 345) = 773 mm^2. Net section at gusset bolt holes also checked. 2L65x65x6 (Ag = 14.8 cm^2 = 1,480 mm^2) provides ample capacity with 50 percent utilization.

Maximum diagonal force (end panel): V = 96 kN (shear at support). Diagonal length = sqrt(4^2 + 2.4^2) = 4.66 m. Diagonal force = 96 x 4.66 / 2.4 = 186 kN (tension in Pratt truss).

Slenderness limits by code

Member type AISC 360 AS 4100 EN 1993 CSA S16
Compression chord KL/r <= 200 Cl. 6.3.3 (KL/r <= 180) lambda_bar per Cl. 6.3.1 Cl. 10.4.2.1 (KL/r <= 200)
Compression web KL/r <= 200 KL/r <= 180 Same KL/r <= 200
Tension member KL/r <= 300 (preferred) KL/r <= 300 (Cl. 7.4) No formal limit KL/r <= 300
Redundant member No code limit KL/r <= 350 No formal limit No code limit

AISC 360 Section E2 provides the compression capacity equation. AS 4100 Clause 6.3.3 uses the column curve approach with alpha_b based on section type. EN 1993 uses buckling curves a through d. CSA S16 Clause 13.3 mirrors the AISC approach.

Secondary bending

In practice, truss members are connected by gusset plates that provide partial moment fixity, not true pins. This generates secondary bending moments in the members, particularly:

AISC Steel Construction Manual Part 14 recommends accounting for secondary bending when the ratio of secondary moment to member capacity exceeds 0.10. For most Pratt and Warren trusses with loads applied at panel points, secondary effects add 5-10 percent to member demand.

Common pitfalls

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Related references

Disclaimer

This page is for educational and reference use only. It does not constitute professional engineering advice. All design values must be verified against the applicable standard and project specification before use. The site operator disclaims liability for any loss arising from the use of this information.