The Effective Length Concept — AISC 360-22 Commentary C-A-7
The effective length KL of a column is the length of an equivalent pin-ended column that would have the same Euler buckling load as the actual column with its actual end restraints. The K factor relates the effective length to the unbraced length L:
Pcr = pi^2 x E x I / (K x L)^2
K depends on:
- The rotational restraint at each end of the column (beam stiffnesses framing in)
- Whether lateral translation of the joint is prevented (sidesway inhibited) or not (sidesway uninhibited)
- The axial load distribution in the column
Sidesway Inhibited vs. Uninhibited — Chapter C
AISC 360-22 makes a fundamental distinction between two frame behaviours:
Sidesway inhibited (braced frame): Lateral stability is provided by a bracing system (X-bracing, shear walls, concrete cores). Columns buckle in single-curvature mode between floors. End moments can reverse curvature but the ends do not translate laterally relative to one another.
For sidesway-inhibited frames: K is bounded between 0.5 and 1.0.
- K = 0.5: both ends fully fixed (theoretical minimum)
- K = 0.7: one end fixed, one end pinned
- K = 1.0: both ends pinned (fundamental case)
Sidesway uninhibited (moment frame / sway frame): The frame resists lateral loads through flexure in the columns and beams. Columns can buckle in a sway mode where the ends translate laterally relative to one another.
For sidesway-uninhibited frames: K >= 1.0 and can exceed 100 for very flexible frames.
- K = 1.0: both ends fixed against rotation but free to translate
- K = 2.0: one end fixed (rotation + translation), one end free (cantilever)
- Practical maximum: K = 3.0 to 5.0 for flexible moment frames
G Factors and Alignment Charts — Commentary Figures C-A-7.1 and C-A-7.2
The Jackson-Moreland alignment charts (nomographs) provide K values based on the relative rotational stiffness at the top (GA) and bottom (GB) of each column:
GA = sum(Ic/Lc) / sum(Ib/Lb) at joint A (top) GB = sum(Ic/Lc) / sum(Ib/Lb) at joint B (bottom)
Where Ic/Lc is the column stiffness ratio and Ib/Lb is the beam stiffness ratio, summed over all members rigidly connected at the joint.
End condition adjustments:
- Pinned end (theoretical): G = infinity (use G = 10.0 for practical calculations)
- Fixed end (theoretical): G = 0 (use G = 1.0 for practical calculations)
To use the chart: Draw a straight line between GA (left scale) and GB (right scale). Read K at the intersection with the centre scale. For sidesway-inhibited frames, use Figure C-A-7.1. For sidesway-uninhibited frames, use Figure C-A-7.2.
For sidesway-uninhibited frames with column inelasticity, the alignment chart is unconservative. AISC recommends applying the stiffness reduction factor tau_b = 0.8 (or the inelastic K formula from the Commentary).
K Factor Quick Reference Table
| End Condition (Sidesway Inhibited) | Theoretical K | Recommended Design K |
|---|---|---|
| Both ends fixed | 0.50 | 0.65 |
| One end fixed, one end pinned | 0.70 | 0.80 |
| Both ends pinned | 1.00 | 1.00 |
| One end fixed, one end free (sway) | 2.00 | 2.10 |
| One end fixed, one end guided (sway) | 2.00 | 2.00 |
For sidesway-uninhibited frames, the AISC commentary recommends K = 1.0 as a minimum.
Direct Analysis Method — AISC 360-22 Chapter C
AISC 360-22 Appendix 1 (now integrated into Chapter C) endorses the Direct Analysis Method (DAM) as the preferred stability analysis approach for all steel frames. Under DAM:
- A second-order analysis (P-Delta and P-delta effects) is mandatory.
- Notional loads of 0.002 x Yi (gravity load at each level) are applied to model initial out-of-plumbness.
- Stiffness reduction: EI* = 0.8 x tau_b x EI for all members contributing to lateral stability, where tau_b = 1.0 when alpha x Pr/Py <= 0.5.
- K = 1.0 for all columns when using DAM — the second-order effects and stiffness reduction replace the need for K > 1.0.
This eliminates the alignment chart uncertainties and provides a consistent, rational treatment of frame stability. DAM is mandatory for frames with delta_2nd / delta_1st > 1.5.
Worked Example — Braced Frame Column
A W12x65 column (A992 steel, Ix = 533 in^4) in a braced frame has unbraced length Lc = 14 ft. Beams framing into the top: W18x35, Lb = 30 ft, Ib = 510 in^4. Bottom: essentially fixed (GB = 1.0).
G factors: Ic/Lc = 533 / (14 x 12) = 3.17 in^3 At top: two W18x35 beams restrain the column. For sidesway-inhibited, multiply beam stiffness by 1.5: Ib/Lb = 510 / (30 x 12) = 1.42 in^3 GA = 3.17 / (2 x 1.5 x 1.42) = 0.74
From Figure C-A-7.1 (sidesway inhibited): GA = 0.74, GB = 1.0, K = 0.79
Effective length: KL = 0.79 x 14 = 11.1 ft. The elastic buckling load about the strong axis: Pcr = pi^2 x 29000 x 533 / (0.79 x 14 x 12)^2 = 4,820 kips
For design, use the column curve per Chapter E to compute phi_Pn from KL/r and Fy = 50 ksi.
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