----------------------------------- | :--------------: | :-------------: | | Both ends pinned | 1.0 | N/A (mechanism) | | One end fixed, one pinned | 0.85 | 2.0 | | Both ends fixed (no rotation) | 0.70 | 1.0 | | One end fixed, one free (cantilever) | 2.2 | 2.2 | | Typical floor column in braced building | 0.85 | — | | Ground floor column, pinned base | 0.90 | — |

For sway frames, K must be determined by rational buckling analysis per Clause 4.7.2, not from this table.


AS 4100 Column Curve — alpha_c Table (Selected Values)

The full alpha_c factor per AS 4100 Table 6.3.3(3) is a function of the modified slenderness lambda_n and the section constant alpha_b:

lambda_n alpha_c (alpha_b = 0.5, UB/UC) lambda_n alpha_c
0 1.000 90 0.681
10 1.000 100 0.598
20 0.978 110 0.518
30 0.941 120 0.447
40 0.892 130 0.387
50 0.843 140 0.336
60 0.789 150 0.295
70 0.734 160 0.261
80 0.706 180 0.208

For lambda_n <= 13.5 (the plateau), alpha_c = 1.0. For Australian UC sections in braced frames, typical lambda_n values range from 25-80 for storey-height columns (3.0-5.0 m), giving alpha_c values of 0.978 to 0.706. Columns above lambda_n = 120 are uncommon in multi-storey construction — they indicate insufficient bracing or very slender sections.


Interaction Check — Biaxial Bending (Clause 8.3.4)

For columns with axial load plus moments about both axes, the interaction check per AS 4100 Clause 8.3.4 has two limits:

In-plane (strong-axis bending + axial): N*/(phi Nc) + Mx*/(phi Msx) <= 1.0

Biaxial (both axes + axial): N*/(phi Nc) + Mx*/(phi Msx) + My*/(phi Msiy) <= 1.4 ... AND (N*/(phi Nc))^1.4 + (Mx*/(phi Msx))^1.4 + (My*/(phi Msiy))^1.4 <= 1.0

The second form (exponent 1.4) is typically more conservative for intermediate utilisation levels and should always be checked when My* is significant. The calculator applies both forms and reports the governing utilisation.

Worked Example — Biaxial Loading

Problem: A 200UC52.2 column, Grade 300, effective length 4.0 m, N* = 600 kN, Mx* = 30 kN.m, My* = 15 kN.m (minor axis moment from eccentric connection).

Check 1 — Section capacities:

Check 2 — Linear interaction (Clause 8.3.4 limit 1.4): 600/1305 + 30/153 + 15/53 = 0.460 + 0.196 + 0.283 = 0.939 <= 1.4. OK.

Check 3 — Exponent 1.4 interaction (Clause 8.3.4 governing): (0.460)^1.4 + (0.196)^1.4 + (0.283)^1.4 = 0.335 + 0.112 + 0.184 = 0.631 <= 1.0. OK.

Result: Column is adequate at 63% utilisation. The minor-axis moment from connection eccentricity accounts for 29% of the interaction capacity — always include connection eccentricity in the analysis.


Column Splice Design — AS 4100 Clause 9.4

Column splices in Australian multi-storey construction are typically located 600-1200 mm above the floor level. Per AS 4100 Clause 9.4:

For a 200UC52.2 column splice (bearing type), the splice plates must carry 50% x 800 kN = 400 kN. With 8-M20 Grade 8.8/S bolts in double shear: Vf per bolt = 2 x 79.0 = 158 kN. 8 x 158 = 1264 kN > 400 kN. Bolt shear is adequate. Splice plate (200x200x10 mm, S300) bearing check controls the final design.

Related Australian Resources

FAQ

What is the form factor kf? The form factor kf = Ae/Ag accounts for local buckling in slender sections per AS 4100 Clause 6.2. For compact sections with λ ≤ λey, kf = 1.0. For slender elements, the effective area Ae is reduced based on the effective width per Clause 6.2.4.

Calculation Tips

What is αb for Australian UC sections? Hot-rolled UC, UB, and welded sections with fy ≤ 450 MPa use αb = 0.5 per AS 4100 Table 6.3.3(1). This corresponds to the AISC column curve. Cold-formed sections and very thick sections use different αb values.

How does the effective length factor K affect column capacity? K directly multiplies the effective length in the slenderness calculation: le = K × L. Doubling K doubles λn, which reduces αc significantly. For example, a column with K = 1.0 might have φNc = 1305 kN, while the same column with K = 2.0 (cantilever) would have φNc ≈ 480 kN — a 63% reduction. Proper end restraint characterisation per Clause 4.6.3 is critical for economic design.

What is the full AS 4100 column capacity equation? The Perry-Robertson formulation in AS 4100 Clause 6.3.3 gives αc = ξ × [1 - √(1 - (90/(ξ × λ))²)] where ξ = (λ/90)² + 1 + η and η = αb × (λ - 13.5)/(λ - 15.3 + 2050/αb). For λ ≤ 13.5, αc = 1.0. This formulation accounts for geometric imperfections (αb = 0.5 for hot-rolled sections) and residual stresses.

Can I use UB sections (Universal Beams) as columns? Yes, UB sections can be used as columns. However, UC sections are generally preferred because their more balanced flange width-to-depth ratio provides better minor-axis buckling resistance. When using a UB as a column, always check the minor axis slenderness and consider that UB sections have lower ry/rx ratios than UC sections, making minor axis buckling more critical.


Disclaimer: This content is for educational purposes only. Results must be verified by a licensed professional engineer. Steel Calculator provides preliminary design tools — NOT a substitute for professional engineering judgment.