CSA S16 Base Plate Design — Bearing & Anchor Rod Reference
Complete reference for CSA S16:19 column base plate design including concrete bearing resistance per CSA A23.3, anchor rod design in tension and shear (CSA S16 Clause 25), plate bending for cantilever projections, and the effects of grout pads. Includes a worked example for a W360x262 column base plate with factored loads.
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CSA S16 Base Plate Design — Overview
Base plate design transfers column axial loads and moments into the concrete foundation through bearing on the concrete and tension in anchor rods. Canadian practice follows CSA S16:19 Clause 25 for anchorage, CSA A23.3:19 for concrete bearing, and the CISC Handbook Part 6 for pre-calculated base plate capacities.
The governing limit states for base plate design are:
| Limit State | CSA S16 Clause | Resistance Factor | Governing Element |
|---|---|---|---|
| Concrete bearing | Cl. 25.2 | φc = 0.65 | Base plate / concrete interface |
| Base plate flexure | Cl. 13.5 | φ = 0.90 | Base plate steel |
| Anchor rod tension | Cl. 25.3.3 | φt = 0.67 | Anchor rods in tension |
| Anchor rod shear | Cl. 25.3.4 | φs = 0.55 | Anchor rods in shear |
| Combined tension + shear | Cl. 25.3.5 | φt / φs | Anchor rod interaction |
| Base plate shear lug | Cl. 25.3.6 | φc = 0.65 | Shear lug bearing |
| Column to base plate weld | Cl. 13.13 | φw = 0.67 | CJP or fillet welds |
The Canadian resistance factors for anchor rods (φt = 0.67 for tension, φs = 0.55 for shear) are significantly more conservative than AISC 360 values (φ = 0.75 tension, φ = 0.65 shear). This reflects the greater uncertainty in field-installed anchor rod quality in Canadian construction practice.
Concrete Bearing Resistance (CSA A23.3:19, Clause 10.8)
The bearing resistance of the concrete beneath the base plate governs the required plate area. Per CSA A23.3:19 Clause 10.8.1, the factored bearing resistance is:
Br = φc × 0.85 × f'c × A1 × √(A2 / A1)
where:
Br = factored bearing resistance (N)
φc = 0.65 (resistance factor for concrete)
f'c = specified concrete compressive strength (MPa)
A1 = base plate area (mm²)
A2 = concrete support area (mm²)
√(A2/A1) ≤ 2.0
The confinement factor √(A2/A1) accounts for the increased bearing capacity when the concrete support surface is larger than the base plate. For a base plate cast directly on a large foundation, A2 is typically much larger than A1, giving the full 2.0 multiplier. For base plates on pedestals or piers (common in Canadian bridge construction), the multiplier may be limited.
Design Bearing Strength
For preliminary design, the conservative case (√(A2/A1) = 1.0, no confinement):
Br = 0.65 × 0.85 × f'c × A1 = 0.5525 × f'c × A1
For f'c = 30 MPa concrete: Br = 0.5525 × 30 × A1 = 16.58 × A1 (N/mm² of plate area)
Grout Pad Effects
Grout pads are standard in Canadian construction to level the base plate and provide uniform bearing. CSA S16 Clause 25.2.2 requires:
- Grout compressive strength ≥ 0.85 × f'c at 28 days
- Grout pad thickness: 25 mm to 50 mm typical
- Grout need not be considered in bearing resistance calculations if its compressive strength meets or exceeds that of the concrete
- For grout thickness > 50 mm, reduce Br by 10% unless the grout is reinforced
Base Plate Thickness — Cantilever Bending Model
The base plate thickness is determined from the cantilever bending of the plate beyond the column profile. The critical section is at the face of the column (for W-shapes) or at the face of the tube wall (for HSS columns).
Required Plate Thickness
Per CSA S16:19 Clause 13.5 (flexure), based on the cantilever projection m or n:
t_req = √(4 × w × m² / (φ × Fy))
where:
t_req = required plate thickness (mm)
w = uniform bearing pressure (MPa) = Cf / (B × N)
Cf = factored axial compressive load (N)
B = base plate width (mm)
N = base plate length (mm)
m = critical cantilever projection (mm)
φ = 0.90 (flexure)
Fy = base plate yield strength (MPa), typically 300W
The critical cantilever projection m is the larger of:
m = (N - 0.95 × d) / 2 (for wide-flange columns)
n = (B - 0.80 × bf) / 2 (for wide-flange columns)
For rectangular or square plates, the governing projection is max(m, n, λ × n'), where n' = √(d × bf) / 4 and λ depends on the aspect ratio.
Anchor Rod Design (CSA S16 Clause 25)
Anchor rods transfer tension from the base plate to the concrete foundation. Canadian practice uses ASTM F1554 Grade 36 (Fy = 248 MPa, Fu = 400 MPa) and Grade 105 (Fy = 724 MPa, Fu = 862 MPa) anchor rods, with Grade 36 being the most common for column base plates.
Anchor Rod Tension Resistance (Clause 25.3.3)
Tr = φt × 0.75 × Ab × Fu
where:
Tr = factored tension resistance (N)
φt = 0.67 (resistance factor for anchor rods in tension)
Ab = nominal area of anchor rod (mm²)
Fu = specified minimum tensile strength of anchor rod (MPa)
For a 25 mm diameter ASTM F1554 Grade 36 anchor rod:
- Ab = π × 25² / 4 = 491 mm²
- Tr = 0.67 × 0.75 × 491 × 400 = 98,691 N ≈ 98.7 kN per rod
Compare to AISC 360: φ × Fnt × Ab = 0.75 × 0.75 × 400 × 491 = 110.5 kN — CSA S16 is 11% more conservative.
Anchor Rod Shear Resistance (Clause 25.3.4)
Vr = φs × 0.60 × Ab × Fu
where:
Vr = factored shear resistance (N)
φs = 0.55 (resistance factor for anchor rods in shear)
Ab = nominal area of anchor rod (mm²)
Fu = specified minimum tensile strength (MPa)
For a 25 mm diameter ASTM F1554 Grade 36 anchor rod:
- Vr = 0.55 × 0.60 × 491 × 400 = 64,812 N ≈ 64.8 kN per rod
The CSA S16 shear resistance is substantially more conservative than AISC (0.75 × 0.60 × Ab × Fu = 110.5 kN for the same rod). When designing anchor rods for Canadian projects with lateral loads, expect to need more or larger rods than an equivalent US design.
Combined Tension and Shear (Clause 25.3.5)
When anchor rods are subjected to both tension and shear (typical for moment-resisting base plates):
(Tf / Tr)² + (Vf / Vr)² ≤ 1.0
where:
Tf = factored tension load per rod (N)
Vf = factored shear load per rod (N)
This interaction equation is identical in form to the AISC provision but with different Tr and Vr values. For Canadian practice, the lower Vr and Tr values mean the interaction governs at lower absolute loads.
Anchor Rod Embedment and Edge Distance
CSA S16 Clause 25.3.8 requires minimum embedment for anchor rods based on the development of the rod's yield strength:
le_min = 0.08 × db × Fy / √(f'c) (tension development)
where:
db = anchor rod diameter (mm)
Fy = anchor rod yield strength (MPa)
f'c = concrete compressive strength (MPa)
Minimum edge distances per CSA A23.3:19 Clause 12.3:
- Cast-in anchors: 5 × db to free edge
- Drilled-in anchors (post-installed): per manufacturer's ICC-ES/CCMC evaluation
- Tension-loaded anchors in seismic: 6 × edge distance minimum
Base Plate Design Worked Example
Problem: Design a column base plate for a W360x262 column (Grade 350W) with the following factored loads:
- Cf = 4,500 kN (axial compression)
- Mf = 75 kN·m (minor moment about weak axis)
- Vf = 120 kN (shear)
Design parameters:
- Concrete: f'c = 30 MPa (normal weight)
- Anchor rods: 4 × M24 ASTM F1554 Grade 36
- Grout: 40 mm thick, f'g = 30 MPa
- Base plate steel: 300W (Fy = 300 MPa)
Step 1 — Determine Required Base Plate Area
Required area for bearing (conservative, no confinement):
A1_req = Cf / (φc × 0.85 × f'c) = 4,500,000 / (0.65 × 0.85 × 30) = 271,493 mm²
Try a 600 mm × 500 mm plate:
A1 = 600 × 500 = 300,000 mm² > 271,493 mm² OK
Check bearing resistance including confinement:
A2 = assume 900 mm × 800 mm foundation = 720,000 mm²
√(A2 / A1) = √(720,000 / 300,000) = √2.4 = 1.55 ≤ 2.0 ✓
Br = 0.65 × 0.85 × 30 × 300,000 × 1.55 = 7,706,625 N = 7,707 kN > 4,500 kN ✓
Step 2 — Determine Critical Cantilever Projection
W360x262 properties: d = 379 mm, bf = 338 mm
m = (N - 0.95 × d) / 2 = (600 - 0.95 × 379) / 2 = (600 - 360) / 2 = 120 mm
n = (B - 0.80 × bf) / 2 = (500 - 0.80 × 338) / 2 = (500 - 270) / 2 = 115 mm
n' = √(d × bf) / 4 = √(379 × 338) / 4 = 358 / 4 = 89.5 mm
Governing cantilever: m = 120 mm (largest of m, n, n')
Step 3 — Calculate Required Plate Thickness
Bearing pressure w = Cf / A1 = 4,500,000 / 300,000 = 15.0 MPa
t_req = √(4 × w × m² / (φ × Fy))
t_req = √(4 × 15.0 × 120² / (0.90 × 300))
t_req = √(864,000 / 270)
t_req = √3,200 = 56.6 mm
Try a 60 mm thick plate: t = 60 mm > 56.6 mm OK
Step 4 — Check Anchor Rods
Moment of 75 kN·m about the weak axis creates tension in anchor rods on one side. With 4 rods at 380 mm spacing (460 mm gauge):
Tension per rod (from moment couple about column centreline):
Tf ≈ Mf / (lever arm × 2 rods) = 75 / (0.46 × 2) = 81.5 kN per rod
For M24 F1554 Grade 36 rods (Ab = 353 mm², Fu = 400 MPa):
Tr = φt × 0.75 × Ab × Fu = 0.67 × 0.75 × 353 × 400 = 70,953 N = 70.95 kN
Tf = 81.5 kN > Tr = 70.95 kN → NOT OK
Increase to M30 rods (Ab = 561 mm²):
Tr = 0.67 × 0.75 × 561 × 400 = 112,761 N = 112.8 kN > 81.5 kN OK
Step 5 — Check Anchor Rods in Shear
Total shear Vf = 120 kN shared by 4 rods = 30 kN per rod:
Vr = φs × 0.60 × Ab × Fu = 0.55 × 0.60 × 561 × 400 = 74,052 N = 74.1 kN per rod
Vf/Vr = 30/74.1 = 0.40 < 1.0 OK
Step 6 — Combined Tension and Shear Interaction
(Tf / Tr)² + (Vf / Vr)² = (81.5 / 112.8)² + (30 / 74.1)²
= (0.723)² + (0.405)² = 0.522 + 0.164 = 0.686 ≤ 1.0 OK
Step 7 — Embedment Check
Minimum embedment for M30 rod:
le_min = 0.08 × 30 × 248 / √30 = 0.08 × 30 × 248 / 5.48 = 109 mm
Provide 300 mm embedment (typical detail, well above minimum).
Step 8 — Summary
| Component | Specification |
|---|---|
| Base plate | 600 mm × 500 mm × 60 mm, 300W |
| Anchor rods | 4 × M30 ASTM F1554 Grade 36, 300 mm embedment |
| Grout | 40 mm non-shrink grout, f'g ≥ 30 MPa |
| Column weld | CJP groove weld, full penetration |
| Pedestal | 900 mm × 800 mm, reinforced to suit |
Shear Lugs (CSA S16 Clause 25.3.6)
When anchor rods alone cannot resist the shear force, shear lugs are added to the base plate. A shear lug is a steel section (typically a channel or WT segment) welded to the underside of the base plate and embedded in the concrete pedestal:
Vr_lug = φc × 0.85 × f'c × A_lug_(bearing)
where:
A_lug_(bearing) = projected bearing area of the lug (mm²)
φc = 0.65
The lug depth is limited by edge distance requirements and the pedestal reinforcement layout. Typical lug dimensions in Canadian practice range from 100 mm to 200 mm deep, with thickness matching the base plate.
CSA S16 Base Plate Design — Key Differences from AISC
| Parameter | CSA S16:19 | AISC 360-22 | Impact |
|---|---|---|---|
| Concrete bearing | φc = 0.65 | φc = 0.65 | Identical |
| Plate flexure | φ = 0.90 | φb = 0.90 | Identical |
| Anchor rod tension | φt = 0.67 | φ = 0.75 | CSA 12% more conservative |
| Anchor rod shear | φs = 0.55 | φ = 0.65 | CSA 18% more conservative |
| Combined interaction | (Tf/Tr)² + (Vf/Vr)² ≤ 1.0 | Same | Same formula |
| Grout thickness limit | 50 mm unreinforced | 2 in. (50.8 mm) unreinforced | Nearly identical |
| Minimum embedment | 0.08 × db × Fy / √(f'c) | 4 × db minimum | CSA depends on Fy and f'c |
| Shear lug provision | Clause 25.3.6 | Not explicitly covered | Canadian standard has explicit guidance |
Frequently Asked Questions
What is the resistance factor for concrete bearing in CSA S16 base plate design? CSA S16 Clause 25.2 specifies φc = 0.65 for concrete bearing in base plate design, referenced from CSA A23.3:19. This is the same value used in AISC 360. The factored bearing resistance is Br = φc × 0.85 × f'c × A1 × √(A2/A1), where √(A2/A1) ≤ 2.0 accounts for confinement from the surrounding concrete support.
What grade of anchor rod is most commonly used in Canadian base plate design? ASTM F1554 Grade 36 is the standard anchor rod grade for Canadian column base plates. It has Fy = 248 MPa and Fu = 400 MPa. Grade 105 (Fy = 724 MPa) is used for high-capacity moment connections. Canadian engineers typically specify CSA G40.21 300W as an equivalent Canadian standard for Grade 36 rods.
How does CSA S16 handle combined tension and shear in anchor rods? CSA S16 Clause 25.3.5 uses the interaction equation (Tf/Tr)² + (Vf/Vr)² ≤ 1.0, identical to the AISC approach. However, because the CSA resistance factors for tension (φt = 0.67) and shear (φs = 0.55) are lower than AISC values, the interaction governs at lower absolute loads. This means Canadian base plates typically require more or larger anchor rods than equivalent US designs for the same loading.
What is a shear lug and when is it required in CSA S16 design? A shear lug is a steel section welded to the underside of the base plate that transfers shear to the concrete by bearing. CSA S16 Clause 25.3.6 provides explicit design provisions. A shear lug is required when anchor rod shear capacity alone is insufficient — common in braced frames with high base shear, seismic lateral load resisting systems, and industrial structures with crane loads. The lug bearing resistance is Vr = φc × 0.85 × f'c × projected bearing area, with φc = 0.65.
How does grout affect base plate bearing capacity per CSA S16? CSA S16 Clause 25.2.2 requires grout compressive strength to be at least 85% of the concrete strength. Grout thicknesses up to 50 mm need no special treatment. For thicknesses exceeding 50 mm (without reinforcement), the bearing resistance is reduced by 10%. Canadian practice typically uses 25-50 mm non-shrink grout pads, which do not reduce the design bearing resistance.
Related Pages
- Canada CSA S16 Guide — Full CSA S16:19 steel design reference
- Canadian Steel Beam Sizes — W, WWF, HSS sections per CISC
- Canadian Steel Grades — G40.21 300W to 480W
- CSA S16 Beam Design — Flexure, LTB, shear checks
- Anchor Rod Embedment — Development length and edge distance
- Base Plate Design Checklist — Step-by-step design guide
- Bolted Connection Checklist — Connection design quality control
- Load Combinations Calculator — Canadian load cases per NBCC
This page is for educational reference. CSA S16:19 base plate design must comply with the current edition of CSA S16, CSA A23.3, and NBCC 2020. All results are PRELIMINARY — NOT FOR CONSTRUCTION without independent verification by a licensed Professional Engineer (P.Eng.).